JAVA拾遗

Posted on 2021-03-25 Edited on 2021-11-09 In 计算机科学 Views:

枚举

枚举允许构造函数和抽象方法。

public enum TrafficLight {
    RED(60) { // 这样调用构造函数
        public TrafficLight next() {
            return GREEN;
        }
    }, // 注意此处的逗号
    GREEN(30) {
        public TrafficLight next() {
            return RED;
        }
    }; // 元素列表应置于最前
    private int time;
    public abstract TrafficLight next();
    // 枚举中构造函数必须为private
    private TrafficLight(int time) { this.time = time; }
}

枚举只有一个成员时，就可以作为一种单例实现方式。

单元素的枚举类型已经成为实现Singleton的最佳方式。 ——Joshua Bloch, Effective JAVA

public class Singleton {
    private Singleton() { }
    public static Singleton instance() {
        return SingletonHolder.INSTANCE.getInstance();
    }
    private enum SingletonHolder {
        INSTANCE;
        private Singleton singleton;
        SingletonHolder() {
            singleton = new Singleton();
        }
        public Singleton getInstance() {
            return singleton;
        }
    }
}

可变参数方法

使用可变参数方法时，编译器为其隐式创建一个数组，在方法体中可以数组的形式访问参数列表。

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public static void printArray(int... is) {
    for(int i : is) { ... }
}

泛型(Generic)

容器(Container)

One of the reasons that generic comes out.

1	ArrayList<String> strList = new ArrayList<>();

Declare a generic class.

1	class MyList <T> { … }

Declare a generic function.

1	public <T> T get(int index) { … }

类型擦除(Type Erasure)

If you do this below, you will get an error.

1	new ArrayList<int>(); // ERROR!

ERROR: Type argument can not be basic type.

Types are removed from a JAVA program, before it is executed at runtime.

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public <T> T add(T a, T b) {
    return a + b; // ERROR!
}

ERROR: Operator '+' cannot be applied to 'T', 'T'.

However, similar codes in C++ works.

The reason is that in C++ template can be regarded as advanced macro.

But this one in JAVA is okay.

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public <T> boolean isSame(T a, T b) {
    return a.equals(b);
}

T is just a Object. That's why the argument can not be basic type, and that explains why operator '+' is not allowed.

JAVA can not get anything from type argument, and the declaration below causes error.

1	Class<?> c = ArrayList<String>.class; // ERROR!

This one is correct.

1	Class<?> c = ArrayList.class;

In JAVA, ArrayList<String> and ArrayList<Integer> are the same type.

无界通配符(Unbounded Wildcard) `<?>`

Wildcard(通配符) <?> can be used in variable declarations, but not in the definition of a generic type.

1	Class<?> c = ArrayList.class;

It is the same as the code below.

1	Class<? extends Object> c = ArrayList.class;

上界通配符(Upper Bound Wildcard) `<? extends …>`

Use <? extends …> in function argument when calling T's member method is required.

void printText(List<? extends TextView> textViews) {
    for(TextView tv: textViews) {
        System.out.println(tv.getText());
    }
}

协变(Covariance)

In JAVA, it looks fine but wrong.

1	ArrayList<Fruit> fruits = new ArrayList<Apple>(); // ERROR!

JAVA's generic is invariant(不变的), so List<Base> has no relation to List<Derive>. Covariance means that List<Derive> inherits List<Base>, it’s needed in some situations.

Code like this when covariance is needed.

1	ArrayList<? extends Fruit> fruits = new ArrayList<Apple>();

But the restriction is that any alteration to T type variable is unavailable as well as function with T type parameter is not allowed.

1	fruits.add(Apple()); // ERROR!

So covariance means read-only.

void printText(List<? extends TextView> textViews) {
    for(TextView tv: textViews) {
        System.out.println(tv.getText());
    }
}

逆变(Contravariance)

Contravariance is a totally different situation.

1	ArrayList<? super Apple> apples = new ArrayList<Fruit>();

But there still exists restriction.

1	Apple apple = apples.get(0);

That contravariance means write-only. See this example below.

void addText(List<? Super TextView> textViews) {
    TextView tv = …;
    textViews.add(tv);
}

In a word, follow PECS rule.

PECS Rule

Producer Extends Consumer Super.

多重约束(Multiple Boundary)

So strange because A and B are interfaces, but still keyword extends is used here.

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interface A { … }
interface B { … }
class C <T extends A & B>  { … }

多线程

同步锁

下例为经典的代理卖票问题。

没有同步锁的情况，多个线程同时访问共享的资源，将导致线程不同步，又称线程不安全。

@Override public void run() {
    while(true) {
        synchronized(this) { // 资源共享
            if(ticket > 0) {
                Log.d("TAG", Thread.currentThread().getName()); // 获取线程名
                --ticket;
            } else break;
        }
    }
}

线程池

管理线程，提高程序性能。

可缓存线程池：可回收旧线程；

ExecutorService exec = Executors.newCachedThreadPool();
for(int i = 0; i < 10; ++i) {
    final int index = i; // JAVA8中匿名/局部类的变量捕获
    exec.execute(new Runnable() {
        @Override public void run() {
            ...
        }
    });
}

有限线程池：Executors.newFixedThreadPool(n)，创建一个定长线程池，可控制线程最大并发数；
单一线程池：Executors.newSingleThreadExecutor()，保证所有任务按指定顺序执行，只会用唯一的工作线程来执行任务，相当于线程数量为1的FixedThreadPool。

JNI(Java Native Interface)

使用native关键字，调用操作系统的底层函数，方便代码在不同平台上运作，也是Java和C/C++的桥梁。

public synchronized void start() {
    if(started) throw new IllegalThreadStateException();
    started = true;
    start0();
}
private native void start0();

❽Optional

Optional.ofNullable(user)
    .map(User::getPhone)
    .filter(it -> it.getPassword().equals("password"))
    .ifPresent(System.out::println);

枚举